My Perspective on Astrology: Science or Pseudoscience? | Concept of Time Series

In this episode, we explore the roots of astrology and how it is based on the position of celestial bodies with respect to stars. However, scientific evidence suggests that the gravitational forces exerted by distant stars and planets are not significant enough to have an impact on human personality traits or life events. Studies have failed to demonstrate any patterns or correlations between astrological charts and real-life outcomes. We also discuss the psychological techniques used by astrologers to persuade people of their abilities and how our tendency to seek out patterns can reinforce our beliefs in astrology.

Calculations:

Gravitational force between a person on Earth & planet Jupiter-

G = 6.67430 x 10^-11 m^3 kg^-1 s^-2: This is the gravitational constant.

m1 = 70 kg: This is the mass of the person on Earth.

m2 = 1.898 x 10^27 kg: This is the mass of Jupiter.

r = 7.78 x 10^12 meters: This is the average distance between the person on earth and Jupiter.

Plugging these values into the equation, we get:

F = 6.67430 x 10^-11 m^3 kg^-1 s^-2 x (70 kg x 1.898 x 10^27 kg) / (7.78 x 10^12 m)^2

F = 1.46 × 10^-7 Newtons

Gravitational force between planet Earth & planet Jupiter -

G = 6.67430 x 10^-11 m^3 kg^-1 s^-2: This is the gravitational constant.

m1 = 5.97 x 10^24 kg: This is the mass of Earth.

m2 = 1.898 x 10^27 kg: This is the mass of Jupiter.

r = 7.78 x 10^12 meters: This is the average distance between the person on earth and Jupiter.

Plugging these values into the equation, we get:

F = 6.67430 x 10^-11 m^3 kg^-1 s^-2 x (5.97 x 10^24 kg  x 1.898 x 10^27 kg) / (7.78 x 10^12 m)^2

F = 1.25 × 10^16 Newtons

Gravitational force between a person & a car -

G = 6.67430 x 10^-11 m^3 kg^-1 s^-2: This is the gravitational constant.

m1 = 1500 kg: This is the mass of the car.

m2 = 70 kg: This is the mass of a person.

r = 2 meters: This is distance between car and the person

Plugging these values into the formula, we get:

F = 6.67430 x 10^-11 m^3 kg^-1 s^-2 x (1500 kg x 70 kg) / (2 m)^2

F = 1.75 x 10^-6 Newtons

Bibliography:

Dean, G., & Kelly, I. W. (2003). Astrology: A critical review. Amherst, NY: Prometheus Books.

Seymour, P. (2010). The scientific basis of astrology. New York, NY: Cosimo Books.

Hamaker-Zondag, K. (1991). The astrology chart workbook: Understanding the art of natal interpretation. York Beach, ME: Samuel Weiser.

Topic: History of India | Astrology | Astronomy